A Carnot Engine receives 250 KJ/s of heat from a heat-source reservoir at 525 C and rejects heat to a heat-sink reservoir at 50 C. What is the power developed and heat rejected?

answer:

Dumating si Ibarra kasama si Kapitan Tyago at pinakilala sa mga pari. Nagpakilala si Ibarra kay Damaso ngunit tinanggihan siya ng Padre. Nang nagsimula na ang hapunan, inanyayahan si Ibarra ng Tinyente na pumaroon muli kinabukasan upang magtanghalian . Tumanggi siya dahil uuwi na rin naman siya sa San Diego.

KABANATA III

(Ang Hapunan

Si Juan Crisostomo Ibarra y Magsalin ay ang pagunahing tauhan sa nobela ni Jose Rizal na Noli Me Tangere. Siya ay isang binatang nakapag-aral sa Europa at nang bumalik ng Pilipinas ay nangarap na makapagpatayo ng paaralan sa bayan ng San Diego.

Explanation:

Hello!

"Acetic acid (HC2H3O2) can be prepared by the action of the acetobacter organism on dilute solutions of ethanol (C2H5OH). The equation for the reaction is  

How many milliliters of a 12.5% (by volume) solution of ethanol are required to produce 175 mL of 0.664 M acetic acid? (Density of pure ethanol = 0.789 g/mL.)"

We have the following data:

% m1/m (percent by solute mass/solution mass) = 12.5

Molar Mass (MM) of ethanol (C2H5OH) ≈ 46.07 g/mol

M1 (molarity) = 0.664 M (or 0.664 mol/L)

V1 (initial volume) = 175 ml = 0.175 L

n (number of mol) = ?

m1 (solute mass - ethanol) = ?

m (solution mass) = ?

d (density of pure ethanol) = 0.789 g/ml

v (volume of pure ethanol) = ? (in ml)

Solving:

[First Step] Let's find the number of moles or matter number, let's see:

If:

[Second Step]  We apply the data to the Molarity or Molar Concentration formula and find the mass of the solute (m1), let's see:

[Third Step] We apply the data to the formula of percent solute mass per solution mass and let's find the solution mass, let's see:

[Fourth Step] We apply the data to the density formula and let's find the volume of ethanol, let's see:

The volume is approximately 54.3 ml

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The basic steps to distillation are: Add heat to a liquid mixture with two or more main substances; for example, a water and ethanol mixture. As the liquid heats, components with the lower boiling points will begin to vaporize and rise through the column.

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Explanation:

Hello!

What is the resulting concentration (in mol/L) of aqueous hydrochloric acid if 500 mL of its gaseous form at 300 K and 100 kPa will be dissolved in 100 mL pure water? Use 8.314 kPa*L/(K*mol).

We have the following data:

M (Molarity) = ? (in Mol/L)

n (number of mols) = ? (in mol)

P (Pressure of gas) = 100 kPa

V (volume of gas) = 500 mL → V (volume of gas) = 0.5 L

T (temperature of gas) = 300 K

R (gas constant) = 8.314 kPa*L/(K*mol)

Let's apply the clapeyron equation, let's see:

Now, let's find the Molarity or Molar Concentration, applying the data found in the formula, let's see:

0.200 Mol/L

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I Hope this helps, greetings ... Dexteright02! =)