3⋅(6^12/6^10)

a. 39
b. 92
c. 108
d. 36

Hello !!

Solve the division of powers in first place , solve the potency 6^2 in second place and in last place you solve the multiplication.

3⋅(6^12/6^10)

= 3⋅6^2

= 3⋅36

= 108

Final result : 108 is the answer (alternative C).

I hope I have collaborated !

answer:

Prove\:cotX\:=\:\frac{sin2X}{1-cos2X}

Step-by-step explanation:

answer:

2(n)+4

ps. im not sure

Step-by-step explanation:

pag twice a number, so multiplication tapos twice so 2 tapos a number pwede natin irerepresent si n as number , tapos increased by four so bale

plus 4, ewan pero di ako sure